# Line slope calculator 10x+y=40

**Straight line given by points A[3; 10] and B[4; 0]**

## Calculation:

**Slope-intercept form of line:**y = -10x+40

**Canonical form of the line equation:**10x+y-40 = 0

**Parametric form of the line equation:**

x = t+3

y = -10t+10 ; t ∈ R

**Slope:**m = -10

**Slope angle of line: φ =**-84°17'22″ = -1.4711 rad

**X intercept:**x

_{0}= 4

**Y intercept:**y

_{0}= q = 40

**Distance line from the origin:**d

_{0}= 3.9801

**The length of the segment AB: |AB| =**10.0499

**Vector: AB =**(1; -10)

**Normal vector: n =**(10; 1)

**Midpoint of the segment AB: M =**[3.5; 5]

**Perpendicular Bisector equation:**x-10y+46.5 = 0

**Vector OA = (3; 10) ; |OA| = 10.4403**

**Vector OB = (4; 0) ; |OB| = 4**

**Scalar product OA .OB = 12**

**Angle ∠ AOB = 73°18'3″ = 1.2793 rad**